Brought to you by
India's opening batsman Rohit Sharma on Wednesday reached the 8000-run club during the fifth and final ODI against Australia in Delhi.
The 'Hitman', who has a number of records in the 50-over format to his name, achieved the recent feat in 206 matches and 200 innings. He needed 46 runs in the match to achieve the landmark.
In doing so, Rohit joins former national team skipper Sourav Ganguly as the third fastest batsman in the history to the 8k club. Dada had also scored 8000 runs in 200 innings.
There are only two players who are listed abover Rohit and Ganguly in terms of fastest to 8000 runs. Indian skipper Virat Kohli tops the list, having achieved it in 175 innings, while former South African skipper AB de Villiers is second, having reached the landmark in 182 innings.
While the opener would have been proud of his achievement, his concentration would have been totally on winning his side the match and the series.
At the time of writing, India were 120 for 4 after 24.4 overs, with Rohit batting 50 of 74 balls and Kedar Jadhav arriving at the crease. The Men in Blue needed 153 in just over run a ball.
Earlier in the day, the Aussies had won the toss and chose to bat first. They had come into this game with loads of confidence having managed to level the series 2-2 from being 2-0 down after the two matches.
Usman Khawaja, who is enjoying a run-feast, continued his sensational form by scoring his second century, both of the series and his career. Peter Handscomb, man of the match in Mohali, also played well for his 52.
But a great start, which saw Aussies just one down after 32 overs, was not capitalized by the middle-order, which was rattled by some brilliant bowling. From 175 for 1, the Aussies could only muster 272 for 9 in 50 overs.
In reply, India lost early wickets as both Shikhar Dhawan and skipper Virat Kohli falling cheaply. A small partnership followed between Rohit and Rishabh Pant, but it was also ended prematurely.